Premium Content

New Signal Chain Resources from Texas Instruments:

Back to Basics: Impedance Matching (Part 1)

Date Posted: October 24, 2011 03:46 PM
Author: Lou Frenzel

The term “impedance matching” is rather straightforward. It’s simply defined as the process of making one impedance look like another. Frequently, it becomes necessary to match a load impedance to the source or internal impedance of a driving source.

A wide variety of components and circuits can be used for impedance matching. This series summarizes the most common impedance-matching techniques.

Rationale And Concept

The maximum power-transfer theorem says that to transfer the maximum amount of power from a source to a load, the load impedance should match the source impedance. In the basic circuit, a source may be dc or ac, and its internal resistance (Ri) or generator output impedance (Zg) drives a load resistance (RL) or impedance (ZL) (Fig. 1):

RL = Ri or ZL = Zg

A plot of load power versus load resistance reveals that matching load and source impedances will achieve maximum power (Fig. 2).

A key factor of this theorem is that when the load matches the source, the amount of power delivered to the load is the same as the power dissipated in the source. Therefore, transfer of maximum power is only 50% efficient.

The source must be able to dissipate this power. To deliver maximum power to the load, the generator has to develop twice the desired output power.

Applications

Delivery of maximum power from a source to a load occurs frequently in electronic design. One example is when the speaker in an audio system receives a signal from a power amplifier (Fig. 3). Maximum power is delivered when the speaker impedance matches the output impedance of the power amplifier.

Another example involves power transfer from one stage to another in a transmitter (Fig. 4). The complex (R ± jX) input impedance of amplifier B should be matched to the complex output impedance of amplifier A. It’s crucial that the reactive components cancel each other. One other example is the delivery of maximum power to an antenna (Fig. 5). Here, the antenna impedance matches the transmitter output impedance.

Transmission-Line Matching

This last example emphasizes another reason why impedance matching is essential. The transmitter output is usually connected to the antenna via a transmission line, which is typically coax cable. In other applications, the transmission line may be a twisted pair or some other medium.

A cable becomes a transmission line when it has a length greater than λ/8 at the operating frequency where:

λ = 300/fMHz

For example, the wavelength of a 433-MHz frequency is:

λ = 300/fMHz = 300/433 = 0.7 meters or 27.5 inches

A connecting cable is a transmission line if it’s longer than 0.7/8 = 0.0875 meters or 3.44 inches. All transmission lines have a characteristic impedance (ZO) that’s a function of the line’s inductance and capacitance:

ZO = √(L/C)

To achieve maximum power transfer over a transmission line, the line impedance must also match the source and load impedances (Fig. 6). If the impedances aren’t matched, maximum power will not be delivered. In addition, standing waves will develop along the line. This means the load doesn’t absorb all of the power sent down the line.

Consequently, some of that power is reflected back toward the source and is effectively lost. The reflected power could even damage the source. Standing waves are the distributed patterns of voltage and current along the line. Voltage and current are constant for a matched line, but vary considerably if impedances do not match.

The amount of power lost due to reflection is a function of the reflection coefficient (Γ) and the standing wave ratio (SWR). These are determined by the amount of mismatch between the source and load impedances.

The SWR is a function of the load (ZL) and line (ZO) impedances:

SWR = ZL/ZO (for ZL > ZO)

SWR = ZO/ZL (for ZO > ZL)

For a perfect match, SWR = 1. Assume ZL = 75 Ω and ZO = 50 Ω:

SWR = ZL/ZO = 75/50 = 1.5

The reflection coefficient is another measure of the proper match:

Γ = (ZL – ZO)/(ZL + ZO)

For a perfect match, Γ will be 0. You can also compute Γ from the SWR value:

Γ = (SWR – 1)/(SWR + 1)

Calculating the above example:

Γ = (SWR – 1)/(SWR + 1) = (1.5 – 1)/(1.5 + 1) = 0.5/2.5 = 0.2

Looking at amount of power reflected for given values of SWR (Fig. 7), it should be noted that an SWR of 2 or less is adequate for many applications. An SWR of 2 means that reflected power is 10%. Therefore, 90% of the power will reach the load.

Keep in mind that all transmission lines like coax cable do introduce a loss of decibels per foot. That loss must be factored into any calculation of power reaching the load. Coax datasheets provide those values for various frequencies.

Another important point to remember is that if the line impedance and load are matched, line length doesn’t matter. However, if the line impedance and load don’t match, the generator will see a complex impedance that’s a function of the line length.

Reflected power is commonly expressed as return loss (RL). It’s calculated with the expression:

RL (in dB) = 10log (PIN/PREF)

PIN represents the input power to the line and PREF is the reflected power. The greater the dB value, the smaller the reflected power and the greater the amount of power delivered to the load.

Impedance Matching

The common problem of mismatched load and source impedances can be corrected by connecting an impedance-matching device between source and load (Fig. 8). The impedance (Z) matching device may be a component, circuit, or piece of equipment.

A wide range of solutions is possible in this scenario. Two of the simplest involve the transformer and the λ/4 matching section. A transformer makes one impedance look like another by using the turns ratio (Fig. 9):

N = Ns/Np = turns ratio

N is the turns ratio, Ns is the number of turns on the transformer’s secondary winding, and Np is the number of turns on the transformer’s primary winding. N is often written as the turns ratio Ns:Ns.

The relationship to the impedances can be calculated as:

Zs/Zp = (Ns/Np)2

or:

Ns/Np = √(Zs/Zp)

Zp represents the primary impedance, which is the output impedance of the driving source (Zg). Zs represents the secondary, or load, impedance (ZL).

For example, a driving source’s 300-Ω output impedance is transformed into 75 Ω by a transformer to match the 75-Ω load with a turns ratio of 2:1:

Ns/Np = √(Zs/Zp) = √(300/75) = √4 = 2

The highly efficient transformer essentially features a wide bandwidth. With modern ferrite cores, this method is useful up to about several hundred megahertz.

An autotransformer with only a single winding and a tap can also be used for impedance matching. Depending on the connections, impedances can be either stepped down (Fig. 10a) or up (Fig. 10b).

The same formulas used for standard transformers apply. The transformer winding is in an inductor and may even be part of a resonant circuit with a capacitor.

A transmission-line impedance-matching solution uses a λ/4 section of transmission line (called a Q-section) of a specific impedance to match a load to source (Fig. 11):

ZQ = √(ZOZL)

where ZQ = the characteristic impedance of the Q-section line; ZO = the characteristic impedance of the input transmission line from the driving source; and ZL = the load impedance.

Here, the 36-Ω impedance of a λ/4 vertical ground-plane antenna is matched to a 75-Ω transmitter output impedance with a 52-Ω coax cable. It’s calculated as:

ZQ = √(75)(36) = √2700 = 52 Ω

Assuming an operating frequency of 50 MHz, one wavelength is:

λ = 300/fMHz = 300/50 = 6 meters or about 20 feet

λ/4 = 20/4 = 5 feet

Assuming the use of 52-Ω RG-8/U coax transmission line with a velocity factor of 0.66:

λ/4 = 5 feet (0.66) = 3.3 feet

Several important limitations should be considered when using this approach. First, a cable must be available with the desired characteristic impedance. This isn’t always the case, though, because most cable comes in just a few basic impedances (50, 75, 93,125 Ω). Second, the cable length must factor in the operating frequency to compute wavelength and velocity factor.

In particular, these limitations affect this technique when used at lower frequencies. However, the technique can be more easily applied at UHF and microwave frequencies when using microstrip or stripline on a printed-circuit board (PCB). In this case, almost any desired characteristic impedance may be employed.

The next part of this series will explore more popular impedance-matching techniques.

Part Inventory
Go
powered by:
 

 
  • Wilton Helm
    2 months ago
    Oct 17, 2012

    RF makes much more use of impedence matching than Audio does, although often for reasons other than maximum power transfer. The classic case in RF is where there is a transmission line between the source and load. If the transmission line does not terminate in a load impedance equal to its characteristic impedance, a portion of the waveform will be reflected. That prevents optimal delivery of power to the load. The reflection does not in and of itself cause a loss of power, or even transformation into heat. However, it will cause the waveform to traverse the transmission line multiple times and since all transmission lines have loss, this will increase losses. It can also cause some of it to re-enter the source device where it can also be coverted to heat, or worse, cause voltage ratings to be exceeded and damage the device. Voltage and currents in the transmission line can also damage the transmission line. Matching transmission line to a load does not involve loss, because the transmission line isn't really a resistor, so this is generally a good thing, although, particularly for short transmission lines may not be as necessary as one might assume.

    In digital electronics, transmission lines are often terminated in a high impedance, full well knowing that there will be reflection. While full analysis of this is beyond the scope of this comment, this is done in conjunction with matching the source impedance to the transmission line (often by adding a resistor in series). The reflected signal is absorbed by the source impedance, preventing mutliple reflections, which would degrade the signal.

    In general, for signal integrity purposes, it is necessary to terminate a transmission line at one end (either end) but not both.

    There are many other reasons for termination in RF. Filter performance depends on it. So does mixer performance, etc. As in Audio, transformers work best propertly terminated. But delivering maximum power is often not the reason

  • Wilton Helm
    2 months ago
    Oct 17, 2012

    Impedance and impedance matching is an important but badly misunderstood concept in engineering, and many seasonsed engineers work under mis-conceptions. As Louis has done, the topic is generally introduced by referring to the maximum power transfer theory (which can easily be proved using derivatives from calculus). However, expecially in our world of portiable devices and energy efficiency conciousness, achieving maximum power deliver to the load is rarely a useful goal. Can you imagine applying the principle to devices you plug into a wall socket? The source impedance of the wall socket is orders of magnitude lower than the impedance of the load. In cases where the source impedance is (predominately) resistive, the maximum efficiency that can be achived under matched impedance conditions is 50%! While there are cases where the source is not resistive, the reality is that in many cases it makes more sense to have the source impedance be much lower than the load impedance.

    Martin's comments about audio amplifiers illustrate this, although without directly hitting the target. There are very few cases in current audio practice where impedance matching is done. The source impedance is almost always significantly lower than the load impedance. Not only does this result in energy efficiency, but it also results in less distortion, because the source is lightly loaded and therefore less influenced by the load. It also makes it convenient to parallel multiple loads. One of the few places where impedance matching is useful in Audio is if a transformer is in the path. Transformer performance, especially frequency response is dependent on both source and load impedance.

    I will apply this to RF in another post.

  • Dan Prysby
    1 year ago
    Nov 16, 2011

    One thing to watch out for...
    Rule: To transfer maximum power, the load impedance should match the (complex conjugate) source impedance.
    is sometimes interpeted incorrectly as: "the source impedance should match the load impedance" - Fig 3 seems to imply this when in fact the lower you can make the source impedance, the more power you can transfer to a given load for situations where transmission line effects are not a consideration.

  • ERNIE RICHARDS
    1 year ago
    Nov 09, 2011

    The source resistance need not dissipate outgoing power. If a current source,
    Iout = Vout/Zo be added at the output of the source the output power comes entirely from the added current source as the voltage across the source resistance is 0 for outgoing power, for returned power the source is terminated in Zo. Its the superposition theorem.

  • Jim Luschen
    1 year ago
    Nov 02, 2011

    Louis-

    Close, but you are obviously not an RF engineer. You wrote:

    "The maximum power-transfer theorem says that to transfer the maximum amount of power from a source to a load, the load impedance should match the source impedance."

    You should have written "... should match the COMPLEX CONJUGATE of the source impedance."

    When impedances are real, your statement is correct. But when impedances are imaginary, you are incorrect. Although you kind of get the point across when you later write "the imaginary parts must cancel".

    I like nitpicking...

  • Bill Whitlock
    1 year ago
    Nov 02, 2011

    As pointed out by Martin, amplifiers driving loudspeakers are NOT impedance matched, for all the reasons he cited. I'd like to add that another misconception held by many non-audio folks (and audiophiles, too, thanks to makers of "floobydust" audio cables) is that an audio cable is a transmission line. The purpose of an audio signal cable is to deliver maximum VOLTAGE, not power, to the destination. Toward this end, IEC standards for professional line-level interfaces call for a source (output) impedance of 50 ohms or less and a load (input) impedance of 10 k-ohms or more. Further, it takes an audio cable some 4,000 feet long to just have noticeable transmission line effects at 20 kHz. All shorter cables are accurately represented by a lump of C, R, and coupled L. Therefore, unless you're the telephone company with mile-long cables, source and load impedances do not need to be matched ... to 600 ohms or any other impedance. --- Bill Whitlock, president & chief engineer of Jensen Transformers, Inc. and AES Life Fellow.

  • Martin Willcocks
    1 year ago
    Nov 01, 2011

    This promises to be a very useful series especially to young engineers who haven't really understood the concepts of analog electrical engineering. Matching is important in many applications.

    One caveat, though, is the illustration in Fig. 3 and the idea that, for driving loudspeakers, the proper goal is to match the source and load impedances.

    Here, the source is an active drive circuit, and the loudspeaker usually has some serious mechanical resonances due to the mass of the moving "piston" and the spring provided by the suspension of the piston. These resonances must be damped effectively so that the loudspeaker can accurately reproduce all frequencies within its useful range.

    Therefore, in this case, the driving impedance must be much lower than the load impedance to obtain an adequate damping factor. The low impedance is generally obtained by the use of negative feedback around the amplifier, which also reduces various distortion components to very low levels, typically under 0.1% THD (Total Harmonic Distortion) with correspondingly low IMD (Intermodulation Distortion).

    The power loss in the amplifier depends on the type of amplifier - Class A, B, C or D. With a Class A amplifier, the maximum possible efficiency (output power divided by input DC power) is 50%; with Class AB or B it is higher; Class C can achieve high efficiency with resonant loads, but is not suitable for audio, and class D (switching power amplifiers) can reach well over 95% efficiency while delivering low distortion, but require careful attention to EMC since the high frequency switching can cause electrical interference.

    At audio frequencies, the wavelength is so long that even several feet of wiring to a loudspeaker doesn't reach /8 at any audible frequencies. However, the resistance of the wiring affects the damping factor, so it should be kept as short as possible.

You must log on before posting a comment.

Are you a new visitor? Register Here